Question

show that the relation between AC current and AC voltage in case of AC applied to a resistor is similar to the DC applied to it​

Answer 1

Answer:

Dear Student,

Given:

Length of the wire initially = l1

Length of the wire after it increases by 10%, l2 = l1 + (10/100 )l1 = l1 + (1/10)l1 = (11/10)l1 Area of the wire initially : A1

Area of the wire after it is stretched becomes : A2

Resistance initially of the wire : R1

Resistance after it is stretched : R2

Now, the most important thing to be kept in mind while solving this problem is that volume of the wire remains constant.

Hence, l1A1 = l2A2

We know that resistance( R) is given by the following equation:

R = ρ(l/A)

Where ‘ρ’ is the resistivity of the wire which will remain the same throughout as it is the property of the material of which the wire is made up.

Taking the ratio of the resistances:

Substituting the values of l2 and A2 in the above equation we get,

Answer 2

The resistance value of the resistor in both AC and DC circuits is same irrespective of the frequency of the AC supply voltage. The change in direction of current in AC supply does not affect resistors behavior. So the current in the resistor will rise and fall according to the voltage as it rises and falls.

Above is your answer ☝

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