Show that the relation R in the set ℝ of real numbers defined as R={(a, b): a,b∈ ℝ and a≤ 3} is neither
reflexive, nor symmetric nor transitive
plss answer it anyone relation and function class 12
Answers
Answered by
1
Answer:
R={(a−b):a≤b
3
}
(i) since (a,a)∈
/
R as a≤a
3
is not always true
[Take a = 1/3. then a≤a
3
is not true]
∴R is not reflexive
(ii) Also(a,b)ϵR⇒(b,a)ϵR
[Take a = 1, b=4, ∴1≤4
3
but 4(1)
3
]
∴ R is not symmetric
(iii) Now (a,b)ϵR(b,c)ϵR⇒(a,c)∴R
[Take a=100,b=5,c=3,∴100≤5
3
,5≤3
3
but 100≥3
3
]
R is not symmetric.
Answered by
0
Answer:
R = { (a - b):a≤ b3 } (i) since (a,a) ∉ R as a≤ a3 is not always true[Take a = 1/3. then a≤ a3 is not true] R is not reflexive(ii) Also (a,b)ϵ
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