show that the right circular cone of least curved surface area and given volume has an altitude equal to root 2 times the radius of the base.
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Question:
show that the right circular cone of least curved surface area and given volume has an altitude equal to root 2 times the radius of the base?
Answer:
Let r and h be the radius and height of the cone respectively.
Volume V=1/3 πr2h
=πk/3 -- (constant) r2h=k
or
h=kr2 --- (i)
Surface S = πrl = πr ( √h + √r2)
h=kr/ 2 ---- from (1)
S = πr √k2 / r4 + r2
=πr √k2+r6 / r4
=π √k2 + r6 / r
DS / DR changes sign from -ve to +ve as r increases through the point k2=2r6
⇒S is the least at this point.
From (1) k2 = h2r4
h2r4 = 2r6
h2 = 2r2
h = √2r2
h = r √2
HOPE IT'S HELP YOU
THANK YOU
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