Question

show that the square of any positive integer can be form of 3m+1 .where m is the natural number. justify your answer

Answer 1

hence this is the answer.........

Answer 2

Let a be any positive integer. b=3
r<3
r can be 3m+0,3m+1and3m+2.
a can be 3m, 3m+1 and 3m+2.
We need only 3m+1 as our positive integer.
Now squarring to both sides, we get
2. 2
(a) =(3m+1)
2. 2. 2
a. = (3m) +(1) +2(3m)(1)
2. 2
a. = 9m. +1+6m.
2
a. =9m +6m +1
2
a. =3(3m +2m) +1
2
a. =3m+1 (let 3m+2m=m)..




(This 2 is taken as square here)




Thanks!!!!
Hope you like it.