Question

Show that the square of any positive integer cannot be in the form of 5q + 2 or 5q + 3 for any integer "q" .​

Answer 1

Step-by-step explanation:

yes

now we will take example

ex-1)integer=6

5q+2=6

so it is false

2)integer=12

5q+2=12

5q=12-2

5q=10

q=5

here it is possible

but sometimes it is not possible

so,this is the proof

please mark as branliest answer

Answer 2

Answer:

Number divisible by 5 can be of the form :

d = 5m + r

where, 0 ≤ r < 5

If d = 5m, d² = 5q

where q is some integer and q = 5m²

If d = 5m + 1, d² = 5q + 1

If d = 5m + 2, d² = 5q + 4

If d = 5m + 3, d² = 5q + 4

If d = 5m + 4, d² = 5q +1

Therefore, the square of any positive integer cannot be in the form of 5q + 2 or 5q + 3 for any integer 'q'.