Question

show that the sum of opposite sides of a cyclic quadrilateral is 180 degree

Answer 1

∠BOD = 2 ∠BAD      ∠BAD = 1/2∠ BODSimilarly ∠BCD = 1/2 ∠DOB ∠BAD + ∠BCD = 1/2∠BOD + 1/2 ∠DOB                   =1/2(∠ BOD + ∠DOB)                   = (1/2)X360° = 180° Similarly ∠B + ∠D = 180°


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