Question

show that the sum of three altitudes of a triangle is less than the sum of the three side os the triangles

Answer 1

1.if two isosceles triangle have a common base,prove that the line segment joining their vertices bisects the common base at right angles.

2.show that the sum of three medians of a triangle is less than its perimeter.

Answer 2

Let there be a triangle ABC with its altitudes D, E, and F from vertices A, B and C respectively.

The altitudes form a right angle at their corresponding bases. Also, in a right triangle the hypotenuse is the longest side. Taking the right triangles formed by the altitudes and the sides as the hypotenuse, we observe that in each triangle, the side forms the longest side, i.e,

In triangle ABD, AB is the longest side

In triangle ACF, AC is the longest side

In triangle CBE, BC is the longest side

So, adding all the three, we get that the perimeter of a triangle is greater than the sum of its three altitudes.

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