Show that the sum of two consecutive natural numbers is 132
Answers
Answer:
n2 + n – 132 = 0 Since the answer is a positive integer, throw out -12 answer. The two consecutive positive integers whose product is 132 are 11 and 12.
Please mark as Branliest
Answer:
65.5 and 66.5
Step-by-step explanation:
Assume n as a natural number
n and n+1 are two consecutive natural numbers
According to question, n+n+1=132
n+n+1=132
2n+1=132
2n=131
n=65.5
Let's review what consecutive numbers are to prepare for learning the formula for the sum of consecutive numbers. Consecutive numbers are ones that differ by 1, hence there is always a 1 between any two consecutive numbers. In ascending order, these numerals are followed by one another. For instance, the numbers 11 and 12 occur immediately after one another, and the difference between them is 1, or 1, as 11 comes before 12 and 12 comes after 11. As a result, a series of integers having a common difference of 1 is called an arithmetic sequence. To calculate the sum of successive integers, we thus utilise the formula for an arithmetic series.
#SPJ2