Math, asked by geetharajkumar1983, 6 months ago

show that the tangent at the point theta=pi/6 on the curve r=acos 2theta meets the initial line at a distance of a/(3)^1/2 from the curve​

Answers

Answered by itsbiswaa
11

Answer: the point with rectangular coordinates (1, √3) and polar ... r = 1 + cos(π/2) = 1, so we graph the point at distance 1 from the origin along the ... EXAMPLE 10.1.6 Graph r = 2 sinθ. ... First we substitute for x and y to get (r cos θ)2 + (r sin θ − 1)2 = 1; ... curve hits the origin and does not have a tangent line.

HOPE IT HELPS U

FOLLOW ME

Answered by HorridAshu
9

\huge\bold{\mathtt{\red{A{\pink{N{\green{S{\blue{W{\purple{E{\orange{R}}}}}}}}}}}}}

Answer: the point with rectangular coordinates (1, √3) and polar ... r = 1 + cos(π/2) = 1, so we graph the point at distance 1 from the origin along the ... EXAMPLE 10.1.6 Graph r = 2 sinθ. ... First we substitute for x and y to get (r cos θ)2 + (r sin θ − 1)2 = 1; ... curve hits the origin and does not have a tangent line.

Similar questions