Show that the total linear momentum of an isolated system remains unchanged. (The answer should be according to class 9 level)
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Hey there,
Let there be a mass A of mass m₁ having velocities u₁ and v₁
Let there be a mass B of mass m₂ having velocities u₂ and v₂
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According to 3rd law of Newton, every action has an equal and opposite reaction.
This implies that the force on A due to B is equal and opposite in direction as compared to force on B due to A.
Force on A due to B=-Force on B due to A
Force on A due to B=m₁a₁=m₁(v₁-u₁)/t
Force on B due to A=m₂a₂=m₂(v₂-u₂)/t
m₁(v₁-u₁)=-m₂(v₂-u₂) [By cancelling t]
m₁v₁-m₁u₁=-m₂v₂+m₂u₂
Therefore m₁u₁+m₂u₂=m₁v₁+m₂v₂(Momentum in an isolated system remains conserved).
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Regards
07161020
Ace
Let there be a mass A of mass m₁ having velocities u₁ and v₁
Let there be a mass B of mass m₂ having velocities u₂ and v₂
==================================================
According to 3rd law of Newton, every action has an equal and opposite reaction.
This implies that the force on A due to B is equal and opposite in direction as compared to force on B due to A.
Force on A due to B=-Force on B due to A
Force on A due to B=m₁a₁=m₁(v₁-u₁)/t
Force on B due to A=m₂a₂=m₂(v₂-u₂)/t
m₁(v₁-u₁)=-m₂(v₂-u₂) [By cancelling t]
m₁v₁-m₁u₁=-m₂v₂+m₂u₂
Therefore m₁u₁+m₂u₂=m₁v₁+m₂v₂(Momentum in an isolated system remains conserved).
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Regards
07161020
Ace
pritiroy2003:
It is very helpful
Answered by
1
Answer:
hi
Explanation:
same as above dubaara kyu likhu
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