Question

show that the x² + 5/3x +7 = 0, has not real roots.​

Answer 1

Answer:

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Answer 2

x^2 + 5/3x + 7 = 0

multiply the whole equation by 3

3x^2 + 5x + 21 = 0

x = -b +/- √b^2 - 4ac / 2a. (quadratic equation)

√b^2 - 4ac = √5^2 - 4×3×21

= √ 25 - 252

= √ - 227

Here inside the root it is a negative value which means this equation has no real roots .