Question

show that trajectory of a projectile is a parabola ​

Answer 1

Answer:

♤A body or object upwards at an angle theta other than 90° with horizontal is called projectile. ♤Let projectile is thrown with a initial velocity u at an angle theta there with horizontal. This equation represents equation of parabola. Hence path of projectile(Trajectory) is a parabola..

Answer 2

♤A body or object upwards at an angle theta other than 90° with horizontal is called projectile.

♤Let projectile is thrown with a initial velocity u at an angle theta there with horizontal. This equation represents equation of parabola. Hence path of projectile(Trajectory) is a parabola

Explanation:

Prove that the trajectory of a projectile is parabolic, having the form y = ax + bx2 . To obtain this expression, solve the equation x = v0x t for t and substitute it into the expression for y = v0y t – (1 / 2)gt2 (These equations describe the x and y positions of a projectile that starts at the origin.)