Show that, ΔΗ = ΔU +ΡΔν
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Answer:
::ΔΗ=ΔU+ΡΔV
ΔΗ=ΔU+P(V2-V1)
ΔΗ=ΔU+PV2-PV1
But PV1 = n¡RT
PV2 = n2RT
::ΔΗ= ΔU+ n¡RT - n2RT
ΔΗ= ΔU+RT(n-n2)
::ΔΗ= ΔU+∆nRT
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