Chemistry, asked by lonerohit155, 9 months ago

Show that under conditions of low pressure (and hence low densities), the Dieterici
equation of state reduces to the van der Waals equation of state,​

Answers

Answered by obedaogega
0

Answer:

At low pressure, the van der Waals' equation is reduced to

Z=  PV_{m}/RT  = 1 − a/ RTV_{m}

The van der Waals' equation is

(P+  a/V_{m} ^{2}) (V_{m} - b) = Rt

At low pressure, volume is very giant and also  the correction term b (a constant of tiny value) are often neglected in comparision to very giant value of the volume.

(P+  a/V_{m} ^{2}) (V_{m}) = RT​    

PV_{m} = a/V_{m} = RT

PV_{m} = RT - a/V_{m}

​Divide either sides of the equation with RT

PV_{m}/RT = 1 - a/RTV_{m}

But Z, PV_{m}/RT

Hence, PV_{m}/RT = 1 - a/RTV_{m}

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