Chemistry, asked by lonerohit155, 11 months ago

Show that under conditions of low pressure (and hence low densities), the Dieterici
equation of state reduces to the van der Waals equation of state,​

Answers

Answered by obedaogega
0

Answer:

At low pressure, the van der Waals' equation is reduced to

Z=  PV_{m}/RT  = 1 − a/ RTV_{m}

The van der Waals' equation is

(P+  a/V_{m} ^{2}) (V_{m} - b) = Rt

At low pressure, volume is very giant and also  the correction term b (a constant of tiny value) are often neglected in comparision to very giant value of the volume.

(P+  a/V_{m} ^{2}) (V_{m}) = RT​    

PV_{m} = a/V_{m} = RT

PV_{m} = RT - a/V_{m}

​Divide either sides of the equation with RT

PV_{m}/RT = 1 - a/RTV_{m}

But Z, PV_{m}/RT

Hence, PV_{m}/RT = 1 - a/RTV_{m}

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