Question

Show that Weber = Volt x Second (​

Answer 1

Explanation:

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The SI unit for weber is (m^2 x kg)/(s^2 x A).

One volt equals to one joule/coulomb,

which is : W/Q.

Now, the SI unit for volt is (m^2 x kg)/(s^3 x A). 

now volt x sec = (m^2 x kg x s)/(s^3 x A)

volt x sec = (m^2 x kg)/(s^2 x A)

volt x sec =  weber 

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