Math, asked by skrrrtt07, 8 hours ago

Show that when the number is multiplied by 6, then 8 is added to it, the sum is divided by two, and twice the original number is subtracted from it, then the number is equal to the original number.

Answers

Answered by shahns
0

Answer:

the original number is 4

Step-by-step explanation:

(6x-8/2)-2x=x

6x-2x-8=2x

4x-8=2x

4x-2x=8

2x=8

x=4

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