Question

Show that whenever two conductors

share charges by bringing them into electrical contact, there is a loss of energy?

Answer 1

see the solution of energy loss when two conductors will.share charge

Answer 2

Answer:

Let us consider a capacitor of capacitance C, with a potential difference V between the plates.

There is  a charge +q on one plate and –q on the other.Suppose the capacitor is charged gradually. At any stage ,the charge on the capacitor is q.

Potential of capacitor =q/C.

Small amount of work done in giving an additional charge dq to the capacitor is

dW=q/C *dq

total work done in giving a charge Q to the capacitor is q.

Q=Q

W=1/C Q2/2

Energy stored in the capacitor

U=W=1/2 Q2/C

Put Q=CV

U=1/2 (CV)2/C =1/2 CV2

Put   CV=Q

U=1/2 QV

Thus,   U=1/2 Q2/C =1/2 CV2=1/2 QV

When Q is in coulomb,V is in Volt ,C is in fared .Energy U is in joule.

Energy stored in a capacitor is in the form of electric field energy in the charged capacitor and it resides in the dielectric medium between the plates.