Show that x+1 is a factor of f(x)=x³+3x²+3x+1
Answers
Answered by
2
x+1=0
x=-1
f(x)=x³+3x²+3x+1
f(-1)=(-1)³+3(-1)²+3(-1)+1
= -1+3-3+1
f(-1)=0
since, f(-1)=0
therefore,
x+1 is a factor of f(x)
Answered by
0
Answer:
Let p(x) be a polynomial of any degree and let alpha be any real number .If P(X) is divided by [ X- Alpha]then p {Alpha} equals to zero.
OR
In simple words, for being factor the term must be equal to zero when put in any given equation.....
Hope, it will help you....
If you understand the solution, do mark it as brainliest......
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