Question

show that (x-1) is a factor of x22-1 and also x23-1​

Answer 1

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Answer 2

answer

firstly we put x-1 =0

for finding value of x

x-1=0

x= 1

now x=1 , in the equation

x^22 - 1

= (1)^22 - 1

= 1 -1=0

therefore ,x= 1 satisfies the x^22 - 1

hence, x -1 is the factor of x^22 - 1

again put x= 1 in the equation x^23 - 1

= (1)^23 - 1

= 1 - 1

= 0

therefore ,x= 1 satisfies the x^23 - 1

hence, x -1 is the factor of x^23 - 1