show that (x-1) is a factor of x3-1
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Let, x-1 =0
so, x=1
p(x)= x3-1
p(1)=(1)3-1
=1-1
=0
So, (x-1) is a factor of x3-1.
so, x=1
p(x)= x3-1
p(1)=(1)3-1
=1-1
=0
So, (x-1) is a factor of x3-1.
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