Question

show that x-1 is a factor of x³— 13 x - 12

Answer 1

$p(x) = {x}^{3} - 13x - 12 \\ p(1) = {1}^{3} - 13 \times 1 - 12 \\ p(1) = 1 - 13 - 12 \\ p(1) = 1 - 25 \\ p(1) = - 24$

Therefore,x-1 is not a factor of
x (cube)-13x-12

Hey Mate,

Here Is Your Answer.
Hope It Helped You.

If You Know That How It Comes p(1).
Easily,
x-1=0
x=1
So ,p(x)=1

__________________________________