Show that x^2+6x+10 has no zero.
I didn't understand the question too.
Can anyone explain it nicely..
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If in an equation b^2 - 4ac < 0 then the equation has no roots (imaginary roots).
In this equation:-
a = 1
b = 6
c = 10
b^2 -4ac
= 6^2 - 4 (1)(10)
= 36 - 40
= -4
i.e, b^2-4ac <0 therefore this equation has no roots.
Hope it helps.
If you satisfied mark it brainliest.
In this equation:-
a = 1
b = 6
c = 10
b^2 -4ac
= 6^2 - 4 (1)(10)
= 36 - 40
= -4
i.e, b^2-4ac <0 therefore this equation has no roots.
Hope it helps.
If you satisfied mark it brainliest.
msn5:
yeah that's true
Really
yupp
of course
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