A stone is thrown vertically upward with an initial velocity u from the top of a tower, reaches the ground with a velocity 3u. What is the height of the Tower?
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Answered by
1
you can add them to get the height of the tower.
Ashutosh2004:
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Answered by
7
let we take upper part - ve
& lower part + ve
int u=-u
final v=3u
acceleration=+g
v²= u²+2gh
or 9u²=u²+ 2gh
or h= 8u²/2g= 4u²/g
& lower part + ve
int u=-u
final v=3u
acceleration=+g
v²= u²+2gh
or 9u²=u²+ 2gh
or h= 8u²/2g= 4u²/g
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