Show that x-2 is a factor of x cube-8
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Answered by
1
Step-by-step explanation:
a³-b³=(a-b)(a²+ab+b²)
x³-8=(x-2)(x²+2x+4)
(x³-8)/(x²+2x+4)=(x-2)
(x-2) IS a factor of x³-8…………
Answered by
2
Step-by-step explanation:
x-2 is factor then x=2 is came zero
x³-8 x=2
2²-8
8-8=0
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