Question

show that (x-2) is a factor p(x) = x^3-12x^2+44x-48

Answer 1

Step-by-step explanation:

let,

p(x) = x^3-12x^2+44x-48

g(x)=(x-2) , If g(x)=0 then x=2

=>Dividing p(x) by g(x) Remainder=p(2)

p(2)=2^3-12×2^2+44×2-48=8-48+88-48=96-96=0

=>Now remainder=0 so we can say g(x) is a factor of p(x)....