show that (x-2) is a factor p(x) = x^3-12x^2+44x-48
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Step-by-step explanation:
let,
p(x) = x^3-12x^2+44x-48
g(x)=(x-2) , If g(x)=0 then x=2
=>Dividing p(x) by g(x) Remainder=p(2)
p(2)=2^3-12×2^2+44×2-48=8-48+88-48=96-96=0
=>Now remainder=0 so we can say g(x) is a factor of p(x)....
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