Question

show that x=3+-√10÷4 are root of eqn 16x2=24x+1​

Answer 1

Answer:

Answer

16x

2

−24x−1=0

Compare given equation with the general form of quadratic equation, which is ax

2

+bx+c=0

a=16,b=−24,c=−1

Find Discriminant:

D=b

2

−4ac

=(−24)

2

−4.16.−1

=576+64

=640>0

Roots of equation are real:

x=

2a

−b±

D

=

4

3±

10

Roots are:

x=

4

3+

10

or x=

4

3−

10