Question

Show that x =3 and y = 2 is not solution of the system of simultaneous linear equation 3 x + 4 y= 17 and 4 x-3 y =12​

Answer 1

$\underline { \pink { System \: of \: linear \:equations : }}$

A pair of linear equations in two variables is said to form a system of simultaneous linear equations.

$Given \: equations \: 3x + 4y = 17 \: --(1) \:and \\4x - 3y = 12 \: --(2)$

$Now, Substitute \: x = 3 \: and \: y = 2 \: in \\given \: equations , we \: get$

$i ) 3 \times 3 + 4 \times 2 = 17$

$\implies 9 + 8 = 17$

$\implies 17 = 17 \: \pink { ( True )}$

$ii) 4 \times 3 - 3 \times 2 = 12$

$\implies 12 - 6 = 12$

$\implies 6 = 12 \: \red { ( False ) }$

Therefore.,

$\blue { x = 3 \: and \: y = 2 } \: is \:\red{ not \: a}\\\red{solution} \: of \: given \: system \: of \\simultaneous \: linear \: equations$

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