Question

show that x=bc-/ad is a solution of quadratic equations ad square (ax/b+2c/d)x + bc square =0.​

Answer 1

Step-by-step explanation:

We have, ad2x(abx+2cd)+c2b=0

⟹a2d2bx2+2acdx+c2b=0

⟹a2d2bx2+acdx+acdx+c2b=0

⟹adx(adbx+c)+bc(adbx+c)=0

⟹(adx+bc)(adbx+c)=0

Either adx + bc =0 or (adbx+c)=0

⟹x=−bcad

Hence, x=−bcad is the requirreed solution

Answer 2

Answer:

We have, ad2x(abx+2cd)+c2b=0ad2x(abx+2cd)+c2b=0

⟹a2d2bx2+2acdx+c2b=0⟹a2d2bx2+2acdx+c2b=0

⟹a2d2bx2+acdx+acdx+c2b=0⟹a2d2bx2+acdx+acdx+c2b=0

⟹adx(adbx+c)+bc(adbx+c)=0⟹adx(adbx+c)+bc(adbx+c)=0

⟹(adx+bc)(adbx+c)=0⟹(adx+bc)(adbx+c)=0

Either adx + bc =0 or (adbx+c)=0(adbx+c)=0

⟹x=−bcad⟹x=−bcad

Hence, x=−bcadx=−bcad is the requirreed solution

Step-by-step explanation:

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