Show that x²+2x+7=0 has no real roots.
Answers
Answered by
0
Answer:
discriminant = b^ 2 - 4ac
= 2^2 - 4 × 1 ×7
= 4 - 28
= -24
-24 < 0
therefore discriminant is less than 0 ,
so the equation has no real roots.
Answered by
0
Answer:
x²+2x+7=0
x ki value hi nhi h isme
so find it ans
x=1
(1)²+2×1+7=0
1+2+7=0
10=0
10
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