Question

show that z=5/(1-i)(2-i)(3-i) is purely imaginary number​

Answer 1

Answer:

i/2

purely imaginary number

Step-by-step explanation:

Show that z=5/(1-i)(2-i)(3-i) is purely imaginary number​

Let first Solve Denominator

(1-i)(2-i)(3-i)

= (1 - i) (6 - 2i - 3i + i²)

= ( 1 - i)( 6 - 5i - 1)

= (1 - i)(5 - 5i)

= 5 (1 - i)(1 - i)

= 5 ( 1 + i² - 2i)

= 5 (-2i)

z = 5/(5 (-2i))   =  -1/2i

= -i/2i²

= -i/(-2)

= i/2

purely imaginary number

Answer 2

Answer:

please mark as brainlist!!