Question

show the answer plz
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Answer 1

Answer:

Step-by-step explanation:

Sorry mark as brainlist

Answer 2

Step-by-step explanation:

GE is joined,

Then in parallelogram ADGE and BCGE,

∆HGE and ∆FGE are in the same parallel sides and have same base to the parallelogram ADGE and BCGE respectively,

By Theorem,

ar(∆HGE)=1/2 ar(ADGE) _____1

ar(∆FGE)= 1/2 ar(BCGE) _____2

1+2

=> ar(EFGH)= 1/2 { ar(ADGE) +ar(BCGE)

=> ar(EFGH)= 1/2 ar(ABCD)

proved

Hope it Helps......