Show the derivation of the relationship between cell potential and pH using the Nernst equation. Use the given Equation: H2 ---> 2H + 2e
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A
7
E
cell
=E
calomel
−E
hydrogen
0.67V=0.28−E
hydrogen
E
hydrogen
=−0.39V
E
hydrogen
=E
hydrogen
0
−
n
0.0592
log
[H
+
]
2
P
H2
−0.39=0−
2
0.0592
log
[H
+
]
2
1
13.175=log
[H
+
]
2
1
[H
+
]
2
1
=1.4985×10
13
[H
+
]=2.58×10
−7
pH=−log[H
+
]=−log2.58×10
−7
=6.61
Hence, the pH of the solution is 6.61
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