Chemistry, asked by Anonymous, 10 months ago

show the formation of electrophile ...!

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Answered by apurva4335

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Fuming sulphuric acid, H2S2O7, can be thought of as a solution of SO3 in sulphuric acid - and so is a much richer source of the SO3. Sulphur trioxide is an electrophile because it is a highly polar molecule with a fair amount of positive charge on the sulphur atom.

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