Question

Show the four triangles as shown in the adjoining figure formed by diagonals and sides of a rhombus are congruent.

Answer 1

Answer:

Step-by-step explanation:

will just give an outline of how to prove it. You can write it up in a two-column proof. A rhombus is a parallelogram with four congruent sides. So, all sides of rhombus ABCD are congruent. That is AB ≅ BC ≅ CD ≅ AD We also know that the diagonals of a parallelogram bisect each other. Since a rhombus is a parallelogram, it also has this property. Therefore BE ≅ DE, AE ≅ CE. Therefore all 4 triangles are congruent by SSS.

hope it help's

Answer 2

Answer:

Yes proved

Step-by-step explanation:

given a rhombus is a parallelogram with four congruent sides proof all sides of rhombus ABCD are congruent that is a b is equal to BC is equal to CD is equal to da to prove we know that diagonals of a parallelogram bisect each other at 90 degree has proved one ab is equal to CD (in property of rhombus) of congruent