Physics, asked by mahesh0024, 9 months ago

show to rays a and b travelling from water to air . if the critical angle for water a surface is 48 degree complete the ray diagram showing the refracted rays for each state conditions when they will suffer total internal reflection​

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Answered by hcps00
1

Answer:

ANSWER

The path of each is ray is shown in the above diagram when they pass through the air-water interface.

(i) : Since the critical angle for water air surface is 48

o

. So the rays, for which angle of incidence is less than 48

o

, will get refracted at the surface. While the ray for which angle of incidence is greater than 48

o

will get total internally reflected.

Also, the given has angle of incidence exactly as 48

o

. So it grazes over the water air interface as shown.

(ii) : There are two condition for total internal reflection to occur.

(a) : The light ray must travel from denser medium to rarer medium but not vice- versa.

(b) : Angle of incidence of the ray must be greater than the critical angle. So total internal reflection of ray will occur is ∠i>48

o

.

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Answered by jr321969
1

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