Question

show your solution please help me don't answer if you don't know I need answer right now​

Answer 1

Solution 1 :-

Intercept on x - axis, a = 3

Intercept on y - axis, b = 6.

So equation of line using intercept form is

$\bf \:\dfrac{x}{a} + \dfrac{y}{b} = 1$

On Substituting, a = 3 and b = 6, we get

$\bf \:\dfrac{x}{3} + \dfrac{y}{6} = 1$

$\bf\implies \:\dfrac{2x + y}{6} = 1$

$\bf\implies \:2x + y = 6$

$\bf\implies \:2x + y - 6 = 0.$

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Solution - 2 :-

Intercept on x - axis, a = 8

Intercept on y - axis, b = 4

So equation of line using intercept form is

$\bf \:\dfrac{x}{a} + \dfrac{y}{b} = 1$

On substituting, a = 8 and b = 4, we get

$\bf\implies \:\dfrac{x}{8} + \dfrac{y}{4} = 1$

$\bf\implies \:\dfrac{x + 2y}{8} = 1$

$\bf\implies \:x + 2y = 8$

$\bf\implies \:2y = 8 - x$

$\bf\implies \:y = 4 - \dfrac{1}{2} x$

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