Question

shows a solid cylinder of mass M suspended through two strings wrapped around it find its acceleration the tension in the string and the speed of cylinder as it falls througg distance h

Answer 1

here is ur answer .........

Answer 2

"Net force = mg-2T = $ma \rightarrow 1$

Net force = 2Tr = 1 cm - $\frac {a}{r}$

= 2T = 1 cm - \frac {a}{r^2} \rightarrow 2

From 1 & 2

$a = \frac {mg}{m+\frac {1cm}{r^2}}$

From (ii), $T = 1cm/ 2r^2 [\frac {mg}{m+\frac{1cm}{r^2}}]$

Putting: $1cm=½mr^2$, we get, a = 2/3 g

$T = \frac {mg}{6}$

$V^2 = 2ah = 2(2/3 g) = h$

$V = \sqrt {\frac {4}{3}gh}$"