ShowThat the polynomial
x²+ 6x+ 10
has no Zero.
for first correct answer is will mark as brainliest
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Answer:
Step-by-step explanation:
D = b^2 - 4AC
D = 6^2 - 4 ×1×10
D = 36 - 40
D = -4
Thus discriminant of this equation is negative
This this eq ^n has no real roots
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