Showthatp(x)=x3 –3x2 +2x–6hasonlyonerealzero.
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Answer:
x^3-3x^2+2x-6=0
x^2(x-3)+2(x-3)=0
(x-3)(x^2+2)=0
x-3=0 or x^2+2=0
X=3 or x^2=-2
X=3 or X= √-2 (not valid because it is not a real number)
therefore it has only real zero
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