Showthatthepoints(2, 0),(-2,0),(0,2)aretheverticesofatrianglealsowithreasonthetypeofthetriangle
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A(2,0) B(-2,0)C(0,2) then AB=√(-2-2)^2++0-0)^2=4 ..then BC √(0-2)^2+(2-0)^2=√4+4=√8 then AC= √ (0-2)^2+(2-0)^2= √8.therefore two sides are equal then it is an isosceles triangle.Hope my answer will help you .so PLEASE MARK AS BRAINLIEST
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