∆ SHR ∼ ∆ SVU. In ∆ SHR, SH = 4.5 cm, HR = 5.2 cm, SR = 5.8 cm and
SH
/SV =5
/3 then draw ∆ SVU.
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1st u find the value of the sides of triangle SVU
SH/SV=5/3.
SO 4.5/SV=5/3.
CROSS MULTIPLY IT WE END UP AS
4.5×3=SV×5
13.5=SV×5
13.5÷5=SV
2.7=SV.
SIMILARLY WE GET THE VALUE OF SIDES VU & SU.
VU=5.2×3÷5=3.12~3.1
SU=5.8×3÷5=3.48~=3.5
now using the given measures draw the triangle.
hope u understood .
SH/SV=5/3.
SO 4.5/SV=5/3.
CROSS MULTIPLY IT WE END UP AS
4.5×3=SV×5
13.5=SV×5
13.5÷5=SV
2.7=SV.
SIMILARLY WE GET THE VALUE OF SIDES VU & SU.
VU=5.2×3÷5=3.12~3.1
SU=5.8×3÷5=3.48~=3.5
now using the given measures draw the triangle.
hope u understood .
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