shravans age is four times his sons age.2 years ago,his age was 1 more than 5 times his sons age. find their ages.
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3
Answer:
area of square=side x side
=9×9
=81cm²
Answered by
11
Let the son's age = x
Sharavans age = 4x
2 years ago,
Age of son = x-2
Age of Sharavan = 4x-2
4x-2 = 5(x-2)+1
4x - 2 = 5x - 10 +1
4x - 2 = 5x - 9
4x = 5x - 7
5x - 4x = 7
x = 7
Age of son = 7
Age of Sharavan = 28
... Hope this will help...
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