Question

Shruthi borrows Rs.12000 at 10 % for 3 years simple interest and Shalini borrowed the same amount for same period at 10% per annum compound annually. Who paid more interest and by how much?

Answer 1

Answer:

shalini

Step-by-step explanation:

shalini paid more interest by rs 372

Answer 2

shalini by 372

shruthi: si= 12000x10x3/100

120x10x3

3600

si=3600

shalini=amount=p x(1+R/100)power t

12000x(1+10/100)power 3

12000x(11/10)power 3

12000×11/10×11/10×11/10

12×11×11×11

15972=amount

si=amount-principal

15972-12000

3972=si

shruthi si = 3600

shalini si=3972

shalini si>shruthi si

3972-3600

372

shalini paid more interest than shruthi by 372