Math, asked by hardikpandaya19, 7 months ago

Shweta takes 6 days less than the Ankita bo complete the work. The same work is completed together
in 4 days How many days required to complete the work by Ankita alone?​

Answers

Answered by shivamupadhyay30jun2
2

Answer:

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Step-by-step explanation:

Let the number of days Ankitha takes to complete the work be x.

It is given that Shwetha takes 6 days less than the number of days taken by Ankitha to complete a piece of work, therefore, the number of days Shwetha takes to complete the work is (x−6).

Now, amount of work done by Ankitha in 1 day is

x

1

and amount of work done by Shwetha in 1 day is

x−6

1

.

It is also given that both Shwetha and Ankitha together can complete the same work in 4 days, therefore, amount of work done by both in 1 day is

4

1

.

Thus, we have

x

1

+

x−6

1

=

4

1

x(x−6)

x−6+x

=

4

1

x

2

−6x

2x−6

=

4

1

⇒x

2

−6x=4(2x−6)

⇒x

2

−6x=8x−24

⇒x

2

−6x−8x+24=0

⇒x

2

−14x+24=0

⇒x

2

−12x−2x+24=0

⇒x(x−12)−2(x−12)=0

⇒(x−2)=0,(x−12)=0

⇒x=2,x=12

Since the cost cannot be negative thus, x=20.

Hence, the number of days Ankitha alone takes to complete the work is 12 hours.

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