Question

Shyam went to a Dussehra mela with his father, there he saw a stall
keeper in one of the food stall has a large cylinderical vessel of
base radius 15cm filled upto a height of 32 cm, with juice. He was
selling juice in small cylinderical glasses of radius 3cm upto a 2
height of 8cm and selling it for Rs. 3 each.
1) shyam purchase 1 glass of juice he found it tasty and then he took 2 more glasses. How much litre he drink at all?

2)how would the stall keeper calculate the total money received after selling the juice completely?

3) If the juice seller is putting two ice cube of 2cm×2cm ×2cm. then how much amount of juice displaces from the glass? ​

Answer 1

1) 0.6788 liters

2) Rs. 300

3) 16 cm³

Step-by-step explanation:

Since volume of the cylindrical vessel is represented by

V = $\pi r^{2}h$

Where r = radius of the cylinder

and h = height of the cylinder

Therefore, volume of the juice in the container = $\pi (15)^{2}\times 32$

= 7200π cm³

Volume of the one cylindrical glass = $\pi (3)^{2}\times (8)$

= 72π cm³

= 226.29 cm³

1). Shyam purchased the juice = 3 glasses

Volume of 1 glass = 226.29 cm³

and 1 cm³ = 0.001 litres

Therefore, 226.29 litres = 0.226 litres

So volume of 3 glasses = 0.226×3 = 0.6788 litres

2). Number of glasses of juice contained in the container

= $\frac{\text{Total volume fo the container}}{\text{Volume of one glass}}$

= $\frac{7200\pi }{72\pi }$

= 100 glasses

Since cost of one glass = Rs 3

Therefore, cost of 100 glasses = 100×3 = Rs 300

3). Volume of one cube = 2³ = 8 cm³

Amount of juice displaced from the glass = volume of 2 cubes inserted in the glass

= 2×8

= 16 cm³  

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