Question

SI=rs 1000, R=5%, T=270days. Find principal​

Answer 1

Step-by-step explanation:

P=SI×100/(RT)

1000×100÷(5×270) ×100

7407.4

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Principal=27037.03\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-b-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 270 \: days} \\ \\ : \implies \text{Simple \: interest(S.I) = 1000\:rupees} \\ \\ : \implies \text{Rate(r) = 5\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Principal(p) = ?}$

• According to given question :

$\bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies S.I = \frac{p \times r \times t}{100} \\ \\ : \implies 1000 = \frac{p \times 5\times\frac{270}{365}}{100} \\ \\ : \implies p = \frac{1000 \times 100\times 365}{5 \times 270 } \\ \\ \green{ : \implies \text{p = 27037.03\: rupees}} \\ \\ \green{ \therefore \text{principal = 27037.03\: rupees}} \\ \\ \bold{Basic \: formula\:related\:to\:C.I} \\ \circ \: A = p(1 + \frac{r}{100} )^{t}$