Question

SI unit of a bus starting from rest moves with uniform acceleration of 0.2 m/ s^2, for 300s. calculate the speed acquited and distance moved​

Answer 1

$\LARGE{ \underline{ \pink{ \sf{Required \: answer:}}}}$

In the question, we are provided with the values and measures of physical quantities involved in Kinematics (Study of motion in physics).

GiveN:

• Starts from rest
• Acceleration of the bus = 0.2 m/s²
• Time taken = 300 seconds.

To find the Final velocity and distance covered....?

This can be done by using the three equations of motion which are:

• v = u + at
• s = ut + 1/2 at²
• v² = u² + 2as

So, let's solve by using these equations,

By using first equation of motion,

a = 0.2 m/s²

u = 0 m/s (Initially at rest)

t = 300 s

➝ v = u + at

Plug in the given values,

➝ v = 0 + 0.2(300)

➝ v = 0 + 60 m/s

➝ v = 60 m/s

Hence the final velocity of the body is 60 m/s.

━━━━━━━━━━━━━━━━━━━━

Now we have to find the distance covered by the body. For this we can use the 3rd equation of motion.

• v = 60 m/s
• u = 0 m/s
• a = 0.2 m/s²

➝ v² = u² + 2as

Plugging the given values,

➝ 60² = 0² + 2(0.2)s

➝ 3600 = 0.4s

➝ s = 36000/4 m

➝ s = 9000 m

Hence the distance covered by the bus = 9000 m

And we are done !!!

Answer 2

Explanation:

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$\sf\large\underline\purple{Given:)}$

Starts from rest

Acceleration of the bus = 0.2 m/s²

Time taken = 300 seconds.

$\sf\large\underline\purple{to find:)}$

Final velocity and distance covered....?

$\huge\underline{\underline{\bold{\red{A}\green{n}\orange{s}\pink{w}\blue{e}{r}}}}$

QUESTION solved by these equations

1. v = u + at
2. s = ut + 1/2 at²
3. v² = u² + 2as

now , we see how this question solved by three equation?

By using 1 equation of motion,

a = 0.2 m/s²

u = 0 m/s (Initially at rest)

t = 300 s

put the given values, according to the question

• v = u + at
• v = 0 + 0.2(300)

• v = 0 + 60 m/s

• v = 60 m/s

the final velocity of the body is 60 m/s.

-------••••••••••√••••••••••••-------------

we have to find the distance covered by the body by 3 equation

v = 60 m/s

u = 0 m/s

a = 0.2 m/s²

put the given values ,

• v² = u² + 2as
• 60² = 0² + 2(0.2)s

• 3600 = 0.4s

• s = 36000/4 m

• s = 9000 m

the distance covered by the bus = 9000 m.

distance = 9000 m ; final velocity = 60 m/s

$\sf\large\underline\purple{Given answer by @itzfadedstar:)}$

Thanks