Question

Sia has 5 coins
consisting of some ₹2 coins, some ₹ 5
coins and some₹ 10
coins. If she has 'p'
amount of money,
how many different
values can 'p' have?
10
06
9
8​

Answer 1

Answer:

p should have 10 different values.

Step-by-step explanation:

this is the answer

Answer 2

Given: some ₹2 coins, some ₹ 5 coins and some₹ 10 coins.

To find: different values can 'p' have

Solution:

Let's consider every possible case

Case1: When all 5 coins are of ₹ 5

           5 x 5 = p

           25 = p

Case 2: When all 5 coins are of  ₹ 2

             5 x 2 = p

             10 = p

Case 3: When all 5 coins are of ₹ 10

             5 x 10 = p

             15 = p

Case 4 : When all coins are different

             p = 2+ 5+10

             p = 17

Case 5 : When any two coins are same but third is different

            (i) 2 coins of Rs. 2 and Rs 5 coin

                p= 2 x2+ 5

                p = 4 +5

                p = 9

            (ii) 2 coins of Rs. 2 and Rs 10 coin

                p= 2 x2+ 10

                p = 4 +10

                p = 14

          (ii) 2 coins of Rs. 5 and Rs 2 coin

                p= 2 x5+ 2

                p = 10 +2

                p = 12

          (iv) 2 coins of Rs. 5 and Rs 10 coin

                p= 2 x5+ 10

                p = 10 +10

                p = 20

          (v) 2 coins of Rs. 10 and Rs 2 coin

                p= 2 x10+ 2

                p = 20 + 2

                p = 22

         (vi) 2 coins of Rs. 10 and Rs 5 coin

                p= 2 x10+ 5

                p = 20 +5

                p = 25

There can be 10 values of p. Option A is the correct answer