Question

side BC; CA and BA of triangle To D Q P respectively if angle ACD equal 100 degree and angle QAP equal 35 degree find all angles

Answer 1

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Answer 2

Answer:

< QAP = < BAC = 25°

By exterior angle theorem,

< ACD = < BAC + < ABC

100° = 35° + < ABC

< ABC = 100° - 35°

                  < ABC = 65°

< BCA + < ACD = 180° [ Linear Pair]

< BCA + 100° = 180°

                  < BCA = 80°

                                Thanks guys!!!