Question

Side of a square is 2√2 cm. Its diagonal is -
(I) 4cm (ll)-4cm (lll) 4√2 cm​

Answer 1

Answer :

(I) 4 cm

Step-by-step explanation :

Given,

• Side of the square, a = 2√2 cm

To find,

• the diagonal

Solution,

 

 $\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(4,0){2}{\line(0,1){4}}\multiput(0,0)(0,4){2}{\line(1,0){4}}\put(-0.5,-0.5){\bf D}\put(-0.5,4.2){\bf A}\put(4.2,-0.5){\bf C}\put(4.2,4.2){\bf B}\put(1.5,-0.6){\bf\large a cm}\put(4.4,2){\bf\large a cm} \qbezier(0,0)(0,0)(4,4)\put(1.65,2.1){\sf\large d cm} \end{picture}$

Let the side of the diagonal be "d cm"

Side of the square, a = 2√2 cm

By Pythagoras theorem, (Δ BCD)

   (BD)² = (BC)² + (CD)²

    d² = a² + a²

     d² = 2a²

    d = √2a

Substitute, a = 2√2 cm

   d = √2 (2√2 cm)

   d = 2(√2)² cm

   d = 2(2) cm

   d = 4 cm

The length of the diagonal is 4 cm

Answer 2

Answer:

The length of the diagonal is 4cm.

Hope this help you